[Maths Class Notes] on Graphical Representation of Inverse Trigonometric Functions Pdf for Exam

The Formula of Inverse Trigonometric Functions

Domain and Range of Inverse Trigonometric Formulas

Function 

Domain

Range

x

[-1,1]

[-[frac{pi}{2}], [frac{pi}{2}]]

x

[-1, 1]

[0, [pi] ]

x

R

[-[frac{pi}{2}], [frac{pi}{2}]]

x

R

[0, [pi]]

x

R- [-1, 1]

[0, [pi]] – {[frac{pi}{2}]}

x

R- [-1, 1]

[-[frac{pi}{2}], [frac{pi}{2}]] – {0}

It is important to note the following formulas considering the domain and range of inverse function

  • sin(sin-1x) = x, if -1 ≤ x ≤ 1 and sin-1(sin y) = y if -[frac{pi}{2}] ≤ y ≤ [frac{pi}{2}].

  • cos(cos-1x) = x, if -1 ≤ x ≤ 1 and cos-1(cos y) = y if 0 ≤ y(arccos) ≤ π.

  • tan(tan-1x) = x, if -∞ < x < ∞ and cos-1(cos y) = y if -[frac{pi}{2}] ≤ y(arctan) ≤ [frac{pi}{2}].

  • cot(cot-1x) = x, if -∞ < x < ∞ and cot-1(cot y) = y if 0 < y <π.

  • sec(sec-1x) = x, if -∞ ≤ x ≤ -1 or 1 ≤ x ≤ ∞ and sec-1(sec y) = y if -0 ≤ y ≤ π, y ≠ [frac{pi}{2}].

  • cosec(cosec-1x) = x, if -∞ ≤ x ≤- 1 or 1 ≤ x ≤ ∞ and cosec-1(cosec y) = y if -[frac{pi}{2}] ≤ y ≤ [frac{pi}{2}], y ≠ 0.

Inverse trigonometric functions are also known as ‘arc functions’ because, for a given value of the trigonometric function, they produce the length of arc needed to get the particular value.

Graph of Inverse Trigonometric Function

1 – Arcsine Function

inverse sine function is defined as 

y = arcsin x for – [frac{pi}{2}] ≤ y ≤ [frac{pi}{2}]

y is the angle with sine x which means x = sin y

the graph of y = arcsin x 

()

2 – Arccosine Function

The graph of cosine does not extend beyond the point you see in the graph (if it extended, there would be multiple values of y for each x value and we would no longer have a function). The start and endpoints are indicated with dots (-1,) and (1,0)

()

3 – Arctangent Function

This graph can extend beyond what you see in the positive and negative direction of x and it does not cross the dashed line.

The domain of arctan x is all values of x 

The range for arctan x is  – [frac{pi}{2}] < arctan x < [frac{pi}{2}]

()

4 – Arccotangent Function

The graph of arccotangent extends in the positive and negative x directions. As shown in the graph it does not stop at -8, 8

The domain of arccot x is all values of x 

The range of arccot x is −2π ​< arccot x ≤ 2π​ (arccot x ≠ 0)

()

5 – Arcsecant Function

Here, in the graph of sec inverse x, the curve is defined outside of the portion between -1 and 1. The starting points (-1, π) and (1,0) with dots. 

The domain of arcsec x is all values of x except −1 < x < 1

The range of arcsec x is 0 ≤ arcsec x ≤ π, arcsec x [neq frac{pi}{2}]

()

6 – Arccosecant Function

The graph extends from positive and negative x direction and is not defined between – 1 and 1

The domain of arccsc x is all values of x except – 1 < x < 1

The range 

The range of arccsc x is  – [frac{pi}{2}] ≤ arc csc x ≤ [frac{pi}{2}] , arccsc x [neq 0]

()

Solved Examples of Inverse Trigonometric Functions

1. Find the accurate value of each of the expression in  [0, 2[pi]].

  1. sin-1(−3[sqrt{2}])

  2. cos-1(−2[sqrt{2}])

  3. tan-1[sqrt{3}]

solution:

a. We get – 3 [sqrt{2}] from 30 – 60 – 90 triangle. Therefore, the reference angle for 3 [sqrt{2}] would be 60°. As it is sine it is negative and must be in the third or fourth quadrant. Here the answer is either 4 [frac{pi}{3}] or 5[frac{pi}{3}]

b. From the isosceles right triangle we get -2[sqrt{2}]. The reference angle will be 45° as it is cosine and negative. The angle is either on the second or third quadrant. The answer is 3 [frac{pi}{4}] or 5[frac{pi}{4}]

c. From the 30 – 60 – 90 triangle we get [sqrt{3}]. For the reference angle 60°, a tangent is [sqrt{3}]. In the first and third quadrant, the tangent is positive, therefore, the answer is [frac{pi}{3}] or 4 [frac{pi}{3}]

Note: Every example here has two answers which can be a problem when finding a single inverse for each trigonometric function. So, we have to restrict the domain in which inverse is found.

2. Get the value of (1.1106).

Solution: let B = (1.1106)

Then tan B = 1.1106

B = 48°

Tan 48 = 1.1106

Therefore, (1.1106 ) = 48°.

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