[Maths Class Notes] on Areas Related to Circles Pdf for Exam

An Overview on the Areas Related to Circles Class 10

Mathematics involves the study of various interesting concepts, such as geometry, integers, number system, circles etc. The study of areas related to circles is one such engaging mathematical concept. 

Circles are a circular figures without any edges. According to geometry, these round-shaped figures can be of three or four types. 

You can seek areas related to circles NCERT solutions to score good grades.

Let’s start learning to understand area related to circle class 10 NCERT!

What are Areas Related to Circles?

The areas related to circles represent the number of squares within a circle’s space. If a circle’s every square has an area approximately 1cm2, you need to count all the squares to calculate its area. Geometrically, the area enclosing a circle with radius r equals to πr2. 

Tip: Study all formula of area related to circle to solve problems like a pro!

Exercises on Area Related to Circles Class 10 Solutions

Read the following questions with areas related to circles solutions to score better!

1. What will be the circumference and area of a circle given radius 8 cm? (Sums related to class 10 chapter 12 maths)

Solution: Circumference or perimeter of a circle = 2πr

                                                                               = 2 * 22/7 * 8 = 50.286 cm (approx.)

Area of the circle will be πr2 = 22/7 * 8 * 8 cm2 = 201.143 cm2 (approx.)

2. Suppose, two circles have a radius of 20 cm and 10 cm, respectively. Find the radius of the third circle having a circumference equal to the sum of both circle’s perimeters. (Problem: area related to circle class 10 NCERT)

Solution: Here, we know about the radii of both circles. 

From area related to circle all formula, use perimeter’s formula C = 2* π * r

Radius of 1st circle = 20 cm, and radius of 2nd circle = 10 cm.

Assume, the radius of the 3rd circle to be r. 

Now, perimeter of 1st circle = 2* π* 20 = 40 π

Circumference of 2nd one = 2* π* 10 = 20 π

Given, 3rd circle’s circumference = perimeter of 1st and 2nd circle.

Radius will be 2 * π * r     = (40 + 20) π 

r = 60 π /2 π = 30 cm

3. A car has wheels with a diameter of 70cm each. How many revolutions can each wheel finish in 10 minutes, when the car is running at a speed of 60 km/hour? (Problem – area related to circle class 10 questions with solutions)

Solution: We know that the car wheel’s diameter = 70 cm, and its radius = 35 cm.

Distance travelled in one revolution = wheel’s circumference. 

Therefore, Perimeter = 2πr = 2*π*35 =70 cm

The car’s speed is 60 km/hour = (60 *100000)/60 cm/min = 1,00,000 cm/min. If the distance covered in 10 minutes, then = 1,00,000*10 = 10,00,000 cm

Let, n = no. of complete revolutions, 

If n*distance covered in 1 resolution = distance covered in 10 minutes

Then, n = (10,00,000*7) / (70*22) = 4545.45 (approx.)

So, every wheel will make 4545.45 complete revolutions.

Often, while studying mathematics, pupils face trouble with cumbersome topics. It happens due to lack of proper subject knowledge. For reducing such a crisis, you can take help from areas related to circles class 10 NCERT solutions. Moreover, try seeking area related to circle class 10 extra questions with solutions.

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